Axial Strain from Stress and Modulus
EasyHooke's lawstrain
A linear-elastic material has normal stress 200 MPa and elastic modulus E = 200 GPa. What is its axial strain?
- A0.0001
- B0.001
- C0.01
- D0.1
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Answer: B. 0.001
Equation: Hooke's law for the linear-elastic range, σ = E·ε, so ε = σ/E. Values: σ = 200 MPa is the stress at the marked point. E = 200 GPa is the slope of the line; convert it to the same units as the stress, E = 200,000 MPa. Step 1: ε = 200 / 200,000. Step 2: ε = 0.001, which is dimensionless (mm/mm). Forgetting that 1 GPa = 1,000 MPa gives 1.0; slipping a zero gives 0.01 or 0.0001.
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