Horizontal Component of an Inclined Force
Easyvectorscomponents
A 500 N force acts at 30° above the horizontal. What is its horizontal component?
- A433 N
- B250 N
- C500 N
- D289 N
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Answer: A. 433 N
Fx = F cos θ = 500 · cos 30° = 500 · 0.866 = 433 N. The vertical component is Fy = 500 · sin 30° = 250 N. Mixing up sine and cosine is the most common slip here: cosine goes with the adjacent (horizontal) side.
N
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