Hydraulic Detention Time of a Basin
Easydetention timehydraulics
A treatment basin has a working volume of 1,200 m³ and receives a steady flow of 4,800 m³/day. Its hydraulic detention time is most nearly:
- A2 hours
- B4 hours
- C6 hours
- D12 hours
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Answer: C. 6 hours
Detention time is volume divided by flow: t = V/Q = 1,200/4,800 = 0.25 day = 6 hours. A common slip is inverting the ratio, which gives 4 per day — a turnover rate rather than a time.
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