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One-Way Shear in a Footing Strip

Mediumfootingone-way-shearnet-pressure
A 2.4 m square footing supports a centered 0.4 m square column. Effective depth d = 0.3 m. The uniform net factored upward pressure is 150 kPa (self-weight effects already included). Using a 1.0 m wide strip, with the one-way shear critical section a distance d from the column face, what is the shear demand Vu per meter width?
  1. A150 kN/m
  2. B127.5 kN/m
  3. C252 kN/m
  4. D105 kN/m
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Answer: D. 105 kN/m

Equation: Vu = qu,net × (ℓ − d) × (strip width). Inputs: ℓ = (2.4 − 0.4)/2 = 1.0 m. Substitution: outside length = 1.0 − 0.3 = 0.7 m; Vu = 150(0.7)(1.0) = 105 kN/m. Wrong: 150 kN/m evaluates at the column face (full projection); 127.5 kN/m uses d/2 = 0.15 m (the punching-shear offset) instead of d; 252 kN/m is the total over the full 2.4 m width, not per meter.
kN/m
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