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Pump Shaft Power from Head and Efficiency

Mediumpumpspowerefficiency
A pump moves water at Q = 0.05 m3/s through a total head of 20 m with 80% pump efficiency. What is the required shaft input power? Use ρ = 1,000 kg/m3 and g = 9.81 m/s2.
  1. A6.1 kW
  2. B9.8 kW
  3. C12.3 kW
  4. D24.5 kW
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Answer: C. 12.3 kW

Hydraulic power is ρgQH = (1,000)(9.81)(0.05)(20) = 9,810 W. Shaft input power is hydraulic power divided by efficiency: 9,810/0.80 = 12,262.5 W ≈ 12.3 kW.
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