Surface Overflow Rate of a Settling Basin

Mediumsedimentationoverflow rate
A rectangular sedimentation basin has a surface area of 40 m² and treats a flow of 0.05 m³/s. Its surface overflow rate is most nearly:
  1. A27 m/day
  2. B54 m/day
  3. C108 m/day
  4. D216 m/day
Show solution

Answer: C. 108 m/day

Surface overflow rate is the flow divided by the plan area of the basin, not its volume: vo = Q/A = 0.05/40 = 1.25 × 10⁻³ m/s. Converting, (1.25 × 10⁻³)(86,400) ≈ 108 m/day. Particles settling faster than this rate are removed; the basin depth does not enter the calculation.
Practice this deckUntimed, one problem at a time, with your progress saved.

Related problems

Keep studying