Surface Overflow Rate of a Settling Basin
Mediumsedimentationoverflow rate
A rectangular sedimentation basin has a surface area of 40 m² and treats a flow of 0.05 m³/s. Its surface overflow rate is most nearly:
- A27 m/day
- B54 m/day
- C108 m/day
- D216 m/day
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Answer: C. 108 m/day
Surface overflow rate is the flow divided by the plan area of the basin, not its volume: vo = Q/A = 0.05/40 = 1.25 × 10⁻³ m/s. Converting, (1.25 × 10⁻³)(86,400) ≈ 108 m/day. Particles settling faster than this rate are removed; the basin depth does not enter the calculation.
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