Civil Engineering Tools
BeamTrussMohr's CircleUnit ConversionsCentroidDeflectionBucklingConcreteRebarFE Prep

Ultimate Bearing Capacity in Clay

Mediumbearing capacitystrip footing
For a strip footing, qult = c·Nc + γ·Df·Nq + 0.5·γ·B·Nγ. Given c = 25 kPa, Nc = 5.7, γ = 18 kN/m³, Df = 1 m, Nq = 1 and Nγ = 0, qult is most nearly:
  1. A107 kPa
  2. B143 kPa
  3. C161 kPa
  4. D321 kPa
Show solution

Answer: C. 161 kPa

qult = cNc + γDfNq + 0.5γBNγ = 25(5.7) + 18(1)(1) + 0 = 142.5 + 18 = 160.5 kPa. Dropping the overburden term gives 143 kPa.
Practice this deckUntimed, one problem at a time, with your progress saved.

Related problems

Keep studying