Unknown Flow at a Pipe Junction
Easycontinuitypipe network
At a pipe junction, 0.30 m³/s and 0.20 m³/s flow in from two pipes and 0.15 m³/s flows out in a third. The flow in the fourth pipe, which leaves the junction, is:
- A0.05 m³/s
- B0.15 m³/s
- C0.65 m³/s
- D0.35 m³/s
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Answer: D. 0.35 m³/s
Equation: continuity at a junction, ΣQin = ΣQout. Values: inflows 0.30 and 0.20 m³/s; outflows 0.15 m³/s and the unknown Q. Step 1: ΣQin = 0.50 m³/s. Step 2: Q = 0.50 − 0.15 = 0.35 m³/s. 0.65 adds all flows; 0.05 subtracts the wrong pair; 0.15 copies the other outflow.
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