Webster Optimum Signal Cycle Length

Hardsignalswebster
A signalised intersection has a total lost time of 12 seconds per cycle and a sum of critical flow ratios of 0.75. Using Webster's formula, the optimum cycle length is most nearly:
  1. A46 seconds
  2. B69 seconds
  3. C92 seconds
  4. D115 seconds
Show solution

Answer: C. 92 seconds

Webster's optimum cycle is C₀ = (1.5L + 5)/(1 − Y) = [1.5(12) + 5]/(1 − 0.75) = 23/0.25 = 92 seconds. As Y approaches 1.0 the cycle length grows without bound, which is the formula's way of saying the intersection is at capacity.
Practice this deckUntimed, one problem at a time, with your progress saved.

Related problems

Keep studying