Simply supported beam with a uniform load
A 6 m beam, pinned at the left end and on a roller at the right, carries 10 kN/m over its full length.
- R_A = R_B
- 30 kN
- M_max
- 45 kN·m
›Solution
- Reactions: Total load = 10 × 6 = 60 kN, shared equally: R_A = R_B = 30 kN.
- Shear: Shear starts at +30 kN, falls in a straight line, crosses zero at midspan (3 m) and ends at −30 kN.
- Moment: Maximum moment is at the zero-shear point: M_max = wL²/8 = 10 × 6² / 8 = 45 kN·m at midspan. The diagram is a parabola.