Design Shear Strength of Masonry
Easymasonrysheardesign-strength
A simplified masonry shear model gives Vn = vn An, with net shear area An = 60,000 mm² (gross area 100,000 mm²), nominal shear stress capacity vn = 0.60 MPa, and strength reduction factor φ = 0.80. What is the design shear strength φVn?
- A36.0 kN
- B23.0 kN
- C48.0 kN
- D28.8 kN
Show solutionHide solution
Answer: D. 28.8 kN
Vn = vn An = 0.60 × 60,000 = 36,000 N = 36.0 kN. φVn = 0.80 × 36.0 = 28.8 kN. 36.0 kN is the nominal strength with φ omitted. 23.0 kN applies φ twice (0.64 × 36.0 = 23.04). 48.0 kN uses the gross area (0.80 × 0.60 × 100,000) instead of the net shear area.
N kN
Practice this deckUntimed, one problem at a time, with your progress saved.
Related problems
- Maximum Shear Stress in a Wood Beam · Timber & Masonry
- Average Compressive Stress in Masonry · Timber & Masonry
- Extreme Fiber Stress in Masonry · Timber & Masonry