Disk Inertia About a Tangent Axis
Mediummass moment of inertiaparallel axis
A solid disk has mass 10 kg and radius 0.20 m. Its mass moment of inertia about an axis tangent to its edge and parallel to its central axis is:
- A0.60 kg·m²
- B0.20 kg·m²
- C0.40 kg·m²
- D0.80 kg·m²
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Answer: A. 0.60 kg·m²
Equation: parallel-axis theorem for mass, I = Icm + m·d², with Icm = ½·m·r² for a solid disk about its central axis. Values: m = 10 kg and r = 0.20 m are given. The tangent axis touches the rim and is parallel to the central axis, so the distance between them is d = r = 0.20 m. Step 1: Icm = ½ × 10 × 0.20² = 0.20 kg·m². Step 2: m·d² = 10 × 0.20² = 0.40 kg·m². Step 3: I = 0.20 + 0.40 = 0.60 kg·m². 0.20 kg·m² is the central-axis value only, 0.40 kg·m² is the transfer term only, and 0.80 kg·m² uses the hoop formula m·r² for Icm.
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