Rod Moment of Inertia About Its Center
Easymass moment of inertiarod
A uniform slender rod has mass 10 kg and length 2 m. Its mass moment of inertia about its center, perpendicular to the rod, is:
- A3.33 kg·m²
- B1.67 kg·m²
- C6.67 kg·m²
- D13.3 kg·m²
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Answer: A. 3.33 kg·m²
I = mL²/12 = 10(2²)/12 = 3.33 kg·m². mL²/3 applies about the end, not the center.
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