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Elevation from Differential Leveling

Mediumdifferential leveling
From benchmark BM (elevation 120.00 m): BS 1.25 m, FS 2.10 m to TP1; then BS 1.60 m on TP1, FS 0.95 m to point X. The elevation of X is most nearly:
  1. A119.15 m
  2. B120.20 m
  3. C120.75 m
  4. D119.80 m
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Answer: D. 119.80 m

Equation: at each setup, HI = elevation + BS and next elevation = HI − FS. Values: BM 120.00 m; setup 1 BS 1.25 on BM and FS 2.10 on TP1; setup 2 BS 1.60 on TP1 and FS 0.95 on X. Step 1: HI₁ = 120.00 + 1.25 = 121.25; TP1 = 121.25 − 2.10 = 119.15. Step 2: HI₂ = 119.15 + 1.60 = 120.75; X = 120.75 − 0.95 = 119.80 m. 120.20 swaps the signs of BS and FS; 119.15 stops at TP1; 120.75 forgets the last FS.
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