Quadrant Bearing from Delta E and N
Mediumbearingcoordinates
A line has ΔE = −150 m and ΔN = +260 m. Its quadrant bearing is most nearly:
- AN60°W
- BN30°W
- CS30°W
- DS60°E
Show solutionHide solution
Answer: B. N30°W
ΔN is positive and ΔE is negative, so the line runs to the NW. The angle from north is tan⁻¹(150/260) = 30°, giving N30°W. Using tan⁻¹(260/150) gives 60°.
Practice this deckUntimed, one problem at a time, with your progress saved.
Related problems
- Distance and Bearing Between Two Points · Surveying
- Convert a Bearing to an Azimuth · Surveying
- Distance Between Two Coordinates · Surveying
