Quadrant Bearing from Delta E and N

Mediumbearingcoordinates
A line has ΔE = −150 m and ΔN = +260 m. Its quadrant bearing is most nearly:
  1. AN60°W
  2. BN30°W
  3. CS30°W
  4. DS60°E
Show solution

Answer: B. N30°W

ΔN is positive and ΔE is negative, so the line runs to the NW. The angle from north is tan⁻¹(150/260) = 30°, giving N30°W. Using tan⁻¹(260/150) gives 60°.
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