Max Shear of a Beam Under Uniform Load
Easyshearuniform load
For the same beam - simply supported, L = 8 m, w = 10 kN/m - what is the maximum shear force?
- A40 kN
- B80 kN
- C20 kN
- D10 kN
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Answer: A. 40 kN
Vmax occurs at the supports and equals each reaction: V = w L / 2 = 10 · 8 / 2 = 40 kN. Shear drops linearly to zero at midspan, which is where the moment peaks. 80 kN is the total load.
kN
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