Shear Force in a Beam with a Point Load
Easyshear forcereactions
A simply supported beam spans 10 m with a single 40 kN load 3 m from the left support. The magnitude of the shear force between the load and the right support is most nearly:
- A12 kN
- B20 kN
- C28 kN
- D40 kN
Show solutionHide solution
Answer: A. 12 kN
Equations: reactions from ΣM = 0; shear to the right of a load V = RA − P. Values: span L = 10 m, P = 40 kN at a = 3 m from the left support. Step 1: RB = P·a/L = 40 × 3/10 = 12 kN; RA = 40 − 12 = 28 kN. Step 2: between the load and the right support, V = 28 − 40 = −12 kN, magnitude 12 kN. 28 kN is the left reaction (shear left of the load); 20 kN assumes a midspan load; 40 kN is the load itself.
Practice this deckUntimed, one problem at a time, with your progress saved.
Related problems
- Support Reaction at B of a Simple Beam · Statics & Equilibrium
- Reaction of a Beam with Uniform Load · Statics & Equilibrium
- Fixed-End Moment of a Cantilever Beam · Statics & Equilibrium