Slab Steel Area per Meter Width
Mediumslabflexuresteel-area
A 1.0 m wide slab strip has factored moment Mu = 16 kN·m, fy = 400 MPa, supplied lever arm z = 135 mm, and φ = 0.90. Use Mu ≤ φAsfyz. Minimum steel is separately supplied as 250 mm² per meter. What steel area per meter width is required?
- A296.3 mm²/m
- B329.2 mm²/m
- C250 mm²/m
- D266.7 mm²/m
Show solutionHide solution
Answer: B. 329.2 mm²/m
Equation: As ≥ Mu/(φfyz), then compare with As,min. Inputs: Mu = 16×10⁶ N·mm. Substitution: As = 16×10⁶/[0.90(400)(135)] = 329.2 mm²/m, which exceeds 250, so flexure governs. Wrong: 296.3 mm²/m omits φ; 250 mm²/m takes the minimum although the flexural requirement is larger; 266.7 mm²/m multiplies Mu by φ instead of dividing the capacity by it.
mm m
Practice this deckUntimed, one problem at a time, with your progress saved.
Related problems
- Required Steel Area for a Concrete Beam · Reinforced Concrete
- Temperature and Shrinkage Steel in a Slab · Concrete: Columns, Slabs & Footings
- Punching Shear Perimeter at a Column · Concrete: Columns, Slabs & Footings