Temperature and Shrinkage Steel in a Slab

Easyslabmin-steelshrinkage
A slab is 180 mm thick (effective depth to the steel is d = 150 mm, which is not needed here). Use the supplied minimum distributed reinforcement ratio ρmin = 0.0018 based on gross concrete area. For a 1.0 m wide strip, what is the minimum steel area per meter width?
  1. A324 mm²/m
  2. B270 mm²/m
  3. C648 mm²/m
  4. D32.4 mm²/m
Show solution

Answer: A. 324 mm²/m

Equation: As,min = ρmin·Ag, with Ag = (strip width)(overall thickness h). Substitution: Ag = 1,000(180) = 180,000 mm²; As,min = 0.0018(180,000) = 324 mm²/m. Wrong: 270 mm²/m uses d = 150 mm instead of the gross thickness; 648 mm²/m doubles the result with no basis in the given rule; 32.4 mm²/m is a decimal slip (strip width treated as 100 mm).
mm m
Practice this deckUntimed, one problem at a time, with your progress saved.

Related problems

Keep studying