Design Web Shear Strength of a Steel Beam
Easyshearweb
A rolled steel beam web has shear area Aw = 2,000 mm² (total section area is 5,000 mm²), Fy = 345 MPa, Cv = 1.0, and for this specified case φv = 1.0. Use Vn = 0.6·Fy·Aw·Cv. Find the design web shear strength φvVn.
- A414 kN
- B372.6 kN
- C1,035 kN
- D690 kN
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Answer: A. 414 kN
Equation: φvVn = φv(0.6 Fy Aw Cv). Substitution: Vn = 0.6(345)(2,000)(1.0) = 414,000 N = 414 kN; φv = 1.0 for this stated case, so φvVn = 414 kN. Wrong: 372.6 kN uses the flexural factor 0.90 as φv; 1,035 kN uses the whole-section area 5,000 mm² instead of the web area; 690 kN omits the 0.6 factor (345·2,000).
N kN
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